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lang-js
c.charCodeAt(0)should be insteadc.charCodeAt(c).[190, 160, 173, 152, 53, 234]c.charCodeAt(0)is correct. You get a single character, say, "6", and get the charcode of its zeroth character, again 6, which gives 0x36. If you use c.charCodeAt(c), it will seem to work because "a".charCodeAt("a") is "a".charCodeAt(0), as "a" is not a number. But with 53 - that is, "5" - as Wolfgang Kuehn noticed, you will get "5".charCodeAt("5"), which is the fifth character of "5", which does not exist, and you will get NaN and break the code. charCodeAt() works because the missing argument is considered 0, but is still not correct.