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oguz ismail
oguz ismail
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Something like this should do that:

awk '{ for (i = 1; sub(/foo/, "bar" i); i++) { }; } 1' file

Note that foo is interpreted as a regular expression.

Something like this should do that:

awk '{ for (i = 1; sub(/foo/, "bar" i); i++) { } } 1' file

Note that foo is interpreted as a regular expression.

Something like this should do that:

awk '{ for (i = 1; sub(/foo/, "bar" i); i++) ; } 1' file

Note that foo is interpreted as a regular expression.

Source Link
oguz ismail
oguz ismail
  • 51.8k
  • 16
  • 64
  • 83

Something like this should do that:

awk '{ for (i = 1; sub(/foo/, "bar" i); i++) { } } 1' file

Note that foo is interpreted as a regular expression.