Return to Answer

You can use the strptime function.

For instance, that would give:

myDatetime = datetime.strptime(myString.split(".")[0], "%Y-%m-%dT%H:%M:%S")

[EDIT] Well, I've seen this has been treated in another thread with a better answer than mine: How do I parse an ISO 8601-formatted date and time?

You can use the strptime function.

For instance, that would give:

myDatetime = datetime.strptime(myString.split(".")[0], "%Y-%m-%dT%H:%M:%S")

[EDIT] Well, I've seen this has been treated in another thread with a better answer than mine: How do I parse an ISO 8601-formatted date and time?

You can use the strptime function.

For instance, that would give:

myDatetime = datetime.strptime(myString.split(".")[0], "%Y-%m-%dT%H:%M:%S")

[EDIT] Well, i've seen this has been treated in another thread with a better answer than mine: How do I parse an ISO 8601-formatted date and time?

Regards,

Max

You can use the strptime function.

For instance, that would give:

myDatetime = datetime.strptime(myString.split(".")[0], "%Y-%m-%dT%H:%M:%S")

[EDIT] Well, I've seen this has been treated in another thread with a better answer than mine: How do I parse an ISO 8601-formatted date and time?

You can use the strptime function.

For instance, that would give:

myDatetime = datetime.strptime(myString.split(".")[0], "%Y-%m-%dT%H:%M:%S")

[EDIT] Well, i've seen this has been treated in another thread : How do I parse an ISO 8601-formatted date and time?

Regards,

Max

You can use the strptime function.

For instance, that would give:

myDatetime = datetime.strptime(myString.split(".")[0], "%Y-%m-%dT%H:%M:%S")

[EDIT] Well, i've seen this has been treated in another thread with a better answer than mine: How do I parse an ISO 8601-formatted date and time?

Regards,

Max