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lang-vb
InStrwith something, e.g.If InStr(sBadChar, Mid(MyStr, i, 1) > 0. But it might also be complaining aboutMid(MyStr, i, 1) = "", I don't recall whether that's valid in VB6, but I suspect not. You probably wantMyStr = Left(MyStr, i - 1) & Mid(MyStr, i)Note that you'll also have to handle the fact thatiis now too far ahead (because the string got shorter). You could fix that by looping backward rather than forward (For i = Len(MyStr) To 1 Step -1).