I'm not a metaclass/class specialist but here's a method that works:

To check if the method was overridden, you could try a getattr on the function name, then check the qualified name:

class NetworkAnalyzer(object):
    def __init__(self):
        funcname = "_score_funct"
        d = getattr(self,funcname)
        print(d.__qualname__ == self.__class__.__name__ + "." + funcname)

if _score_funct is defined in LS, d.__qualname__ is LS._score_funct, else it's NetworkAnalyzer._score_funct.

That works if the method is implemented at LS class level. Else you could replace by:

d.__qualname__ != "NetworkAnalyzer." + funcname

Of course if the method is overridden with some code which raises an NotImplementedError, that won't work... This method doesn't inspect methods code (which is hazardous anyway)

I'm not a metaclass/class specialist but here's a method that works in your simple case (not sure it works as-is in a complex/nested class namespace):

To check if the method was overridden, you could try a getattr on the function name, then check the qualified name (class part is enough using string partitionning):

class NetworkAnalyzer(object):
    def __init__(self):
        funcname = "_score_funct"
        d = getattr(self,funcname)
        print(d.__qualname__.partition(".")[0] == self.__class__.__name__)

if _score_funct is defined in LS, d.__qualname__ is LS._score_funct, else it's NetworkAnalyzer._score_funct.

That works if the method is implemented at LS class level. Else you could replace by:

d.__qualname__.partition(".")[0] != "NetworkAnalyzer"

Of course if the method is overridden with some code which raises an NotImplementedError, that won't work... This method doesn't inspect methods code (which is hazardous anyway)

I'm not a metaclass/class specialist but here's a method that works:

To check if the method was overriddent, you could try a getattr on the function name, then check the qualified name:

class NetworkAnalyzer(object):
    def __init__(self):
        funcname = "_score_funct"
        d = getattr(self,funcname)
        print(d.__qualname__ == self.__class__.__name__ + "." + funcname)

if _score_funct is defined in LS, d.__qualname__ is LS._score_funct, else it's NetworkAnalyzer._score_funct.

That works if the method is implemented at LS class level. Else you could replace by:

d.__qualname__ != "NetworkAnalyzer." + funcname

Of course if the method is overridden with some code which raises an NotImplementedError, that won't work...

I'm not a metaclass/class specialist but here's a method that works:

To check if the method was overridden, you could try a getattr on the function name, then check the qualified name:

class NetworkAnalyzer(object):
    def __init__(self):
        funcname = "_score_funct"
        d = getattr(self,funcname)
        print(d.__qualname__ == self.__class__.__name__ + "." + funcname)

if _score_funct is defined in LS, d.__qualname__ is LS._score_funct, else it's NetworkAnalyzer._score_funct.

That works if the method is implemented at LS class level. Else you could replace by:

d.__qualname__ != "NetworkAnalyzer." + funcname

Of course if the method is overridden with some code which raises an NotImplementedError, that won't work... This method doesn't inspect methods code (which is hazardous anyway)