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searchsorted isn't nlog(n) since it doesn't sort the array before searching, it assumes that the argument array is already sorted. check out the documentation of numpy.searchsorted (link above)

Alok Nayak
– Alok Nayak

2018-08-07 16:31:18 +00:00
Commented Aug 7, 2018 at 16:31
It's mlog(n): m binary searches inside a list of length n.

Shillington
– Shillington

2021-04-26 10:32:35 +00:00
Commented Apr 26, 2021 at 10:32
1

Its mlog(n) if m elements are to be searched, when a m shaped array is passed instead of a single element like 3. It is log(n) for this question's requirement which is about finding one element.

Alok Nayak
– Alok Nayak

2021-05-17 10:13:00 +00:00
Commented May 17, 2021 at 10:13

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