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I'm trying to find and replace specific string with sed command but when I run the command nothing seems to be happening.

FIND:

LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined

REPLACE WITH:

LogFormat "%{X-Forwarded-For}i %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" combined

FILE CONTENT

hello
LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined
bye

COMMAND

$ sed -i 's/LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined/LogFormat "%{X-Forwarded-For}i %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" combined/g' /etc/apache2/apache2.conf

I looked into How do I escape double and single quotes in SED? (bash)How do I escape double and single quotes in SED? (bash) but cannot workout what the problem is.

I'm trying to find and replace specific string with sed command but when I run the command nothing seems to be happening.

FIND:

LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined

REPLACE WITH:

LogFormat "%{X-Forwarded-For}i %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" combined

FILE CONTENT

hello
LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined
bye

COMMAND

$ sed -i 's/LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined/LogFormat "%{X-Forwarded-For}i %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" combined/g' /etc/apache2/apache2.conf

I looked into How do I escape double and single quotes in SED? (bash) but cannot workout what the problem is.

I'm trying to find and replace specific string with sed command but when I run the command nothing seems to be happening.

FIND:

LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined

REPLACE WITH:

LogFormat "%{X-Forwarded-For}i %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" combined

FILE CONTENT

hello
LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined
bye

COMMAND

$ sed -i 's/LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined/LogFormat "%{X-Forwarded-For}i %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" combined/g' /etc/apache2/apache2.conf

I looked into How do I escape double and single quotes in SED? (bash) but cannot workout what the problem is.

tag bash removed, no bash problem/question
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Cyrus
Cyrus
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Replacing a string with different string with bash SED comand

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BentCoder
BentCoder
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Replacing a string with different string with bash SED comand

I'm trying to find and replace specific string with sed command but when I run the command nothing seems to be happening.

FIND:

LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined

REPLACE WITH:

LogFormat "%{X-Forwarded-For}i %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" combined

FILE CONTENT

hello
LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined
bye

COMMAND

$ sed -i 's/LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" combined/LogFormat "%{X-Forwarded-For}i %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" combined/g' /etc/apache2/apache2.conf

I looked into How do I escape double and single quotes in SED? (bash) but cannot workout what the problem is.