@Maciek solution works perfect if the declared type of the member variable is the interface / abstract class. It won't work if the declared type is sub-class / sub-interface / sub-abstract class unless we register them all through registerTypeAdapter(). We can avoid registering one by one with the use of registerTypeHierarchyAdapter, but I realize that it will cause StackOverflowError because of the infinite loop. (Please read reference section below)

In short, my workaround solution looks a bit senseless but it works without StackOverflowError.

@Override
public JsonElement serialize(T object, Type interfaceType, JsonSerializationContext context) {
    final JsonObject wrapper = new JsonObject();
    wrapper.addProperty("type", object.getClass().getName());
    wrapper.add("data", new Gson().toJsonTree(object));
    return wrapper;
}

I used another new Gson instance of work as the default serializer / deserializer to avoid infinite loop.

Reference

According to Gson 2.3.1 documentation for JsonSerializationContext and JsonDeserializationContext

Invokes default serialization on the specified object passing the specific type information. It should never be invoked on the element received as a parameter of the JsonSerializer.serialize(Object, Type, JsonSerializationContext) method. Doing so will result in an infinite loop since Gson will in-turn call the custom serializer again.

and

Invokes default deserialization on the specified object. It should never be invoked on the element received as a parameter of the JsonDeserializer.deserialize(JsonElement, Type, JsonDeserializationContext) method. Doing so will result in an infinite loop since Gson will in-turn call the custom deserializer again.

This concludes that below implementation will cause infinite loop and cause StackOverflowError eventually.

@Override
public JsonElement serialize(Animal src, Type typeOfSrc,
        JsonSerializationContext context) {
    return context.serialize(src);
}

@Maciek solution works perfect if the declared type of the member variable is the interface / abstract class. It won't work if the declared type is sub-class / sub-interface / sub-abstract class unless we register them all through registerTypeAdapter(). We can avoid registering one by one with the use of registerTypeHierarchyAdapter, but I realize that it will cause StackOverflowError because of the infinite loop. (Please read reference section below)

In short, my workaround solution looks a bit senseless but it works without StackOverflowError.

@Override
public JsonElement serialize(T object, Type interfaceType, JsonSerializationContext context) {
    final JsonObject wrapper = new JsonObject();
    wrapper.addProperty("type", object.getClass().getName());
    wrapper.add("data", new Gson().toJsonTree(object));
    return wrapper;
}

I used another new Gson instance of work as the default serializer / deserializer to avoid infinite loop. The drawback of this solution is you will also lose other TypeAdapter as well, if you have custom serialization for another type and it appears in the object, it will simply fail.

Still, I am hoping for a better solution.

Reference

According to Gson 2.3.1 documentation for JsonSerializationContext and JsonDeserializationContext

Invokes default serialization on the specified object passing the specific type information. It should never be invoked on the element received as a parameter of the JsonSerializer.serialize(Object, Type, JsonSerializationContext) method. Doing so will result in an infinite loop since Gson will in-turn call the custom serializer again.

and

Invokes default deserialization on the specified object. It should never be invoked on the element received as a parameter of the JsonDeserializer.deserialize(JsonElement, Type, JsonDeserializationContext) method. Doing so will result in an infinite loop since Gson will in-turn call the custom deserializer again.

This concludes that below implementation will cause infinite loop and cause StackOverflowError eventually.

@Override
public JsonElement serialize(Animal src, Type typeOfSrc,
        JsonSerializationContext context) {
    return context.serialize(src);
}