Another Bypass-Style Solution:
instead of using this., you can use super..

• A prerequisite is to create two classes, one as a Base Class, another as a Usable Class.
• The Base Class contains the methods that you want to call in the constructor.
• The Usable Class calls the Method from within it's constructor using super.myMethod(); instead of this.myMethod();

This is a subtle benefit made easily possible thanks to Typescript. :)

Example:
Source: Typescript Bypass Solution on Stackoverflow

export class myBaseClass
{
    constructor(ctx:any)
    {
        this.ctx = ctx;         // Audio context saved into member variable of class
    }
    myBaseMethod()
    {
        // Do Complex Work
    }
}

export class myUsableClass extends myBaseClass
{
    constructor(ctx:any)
    {
        super(ctx);
        super.myBaseMethod(); // Use super., Not this.
    }
    
}

Another Bypass-Style Solution:
instead of using this., you can use super..

• A prerequisite is to create two classes, one as a Base Class, another as a Usable Class.
• The Base Class contains the methods that you want to call in the constructor.
• The Usable Class calls the Method from within it's constructor using super.myMethod(); instead of this.myMethod();

This is a subtle benefit made easily possible thanks to Typescript. :)

Example:
Source: Typescript Bypass Solution on Stackoverflow

export class myBaseClass
{
    constructor(ctx:any)
    {
        this.ctx = ctx;         // Audio context saved into member variable of class
    }
    myBaseMethod()
    {
        // Do Complex Work
    }
}

export class myUsableClass extends myBaseClass
{
    constructor(ctx:any)
    {
        super(ctx);
        super.myBaseMethod(); // Use super., Not this.
    }
    
}