Revisions to How to automatically run the executable in GDB?

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gdb -ex run ./a.out

If you need to pass arguments to a.out:

gdb -ex run --args ./a.out arg1 arg2 ...

EDIT: Orion Orion says this doesn't work on Mac OSX.

The -ex flag has been available since GDB-6.4 (released in 2005), but OSX uses Apple's fork of GDB, and the latest XCode for Leopard contains GDB 6.3.50-20050815 (Apple version gdb-967), so you are out of luck.

Building current GDB-7.0.1 release is one possible solution. Just be sure to read this.

gdb -ex run ./a.out

If you need to pass arguments to a.out:

gdb -ex run --args ./a.out arg1 arg2 ...

EDIT: Orion says this doesn't work on Mac OSX.

The -ex flag has been available since GDB-6.4 (released in 2005), but OSX uses Apple's fork of GDB, and the latest XCode for Leopard contains GDB 6.3.50-20050815 (Apple version gdb-967), so you are out of luck.

Building current GDB-7.0.1 release is one possible solution. Just be sure to read this.

gdb -ex run ./a.out

If you need to pass arguments to a.out:

gdb -ex run --args ./a.out arg1 arg2 ...

EDIT: Orion says this doesn't work on Mac OSX.

The -ex flag has been available since GDB-6.4 (released in 2005), but OSX uses Apple's fork of GDB, and the latest XCode for Leopard contains GDB 6.3.50-20050815 (Apple version gdb-967), so you are out of luck.

Building current GDB-7.0.1 release is one possible solution. Just be sure to read this.

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edited Mar 30, 2015 at 22:08

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gdb -ex run ./a.out

If you need to pass arguments to a.out:

gdb -ex run --args ./a.out arg1 arg2 ...

EDIT: Orion says this doesn't work on Mac OSX.

The -ex flag has been available since GDB-6.4 (released in 2005), but OSX uses Apple's fork of GDB, and the latest XCode for Leopard contains GDB 6.3.50-20050815 (Apple version gdb-967), so you are out of luck.

Building current GDB-7.0.1 release is one possible solution. Just be sure to read this.

gdb -ex run ./a.out

EDIT: Orion says this doesn't work on Mac OSX.

The -ex flag has been available since GDB-6.4 (released in 2005), but OSX uses Apple's fork of GDB, and the latest XCode for Leopard contains GDB 6.3.50-20050815 (Apple version gdb-967), so you are out of luck.

Building current GDB-7.0.1 release is one possible solution. Just be sure to read this.

gdb -ex run ./a.out

If you need to pass arguments to a.out:

gdb -ex run --args ./a.out arg1 arg2 ...

EDIT: Orion says this doesn't work on Mac OSX.

The -ex flag has been available since GDB-6.4 (released in 2005), but OSX uses Apple's fork of GDB, and the latest XCode for Leopard contains GDB 6.3.50-20050815 (Apple version gdb-967), so you are out of luck.

Building current GDB-7.0.1 release is one possible solution. Just be sure to read this.

Added Mac OSX specifics

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edited Jan 25, 2010 at 22:23

Employed Russian

216.9k
36
324
396

gdb -ex run ./a.out

EDIT: Orion says this doesn't work on Mac OSX.

The -ex flag has been available since GDB-6.4 (released in 2005), but OSX uses Apple's fork of GDB, and the latest XCode for Leopard contains GDB 6.3.50-20050815 (Apple version gdb-967), so you are out of luck.

Building current GDB-7.0.1 release is one possible solution. Just be sure to read this.

gdb -ex run ./a.out

gdb -ex run ./a.out

EDIT: Orion says this doesn't work on Mac OSX.

The -ex flag has been available since GDB-6.4 (released in 2005), but OSX uses Apple's fork of GDB, and the latest XCode for Leopard contains GDB 6.3.50-20050815 (Apple version gdb-967), so you are out of luck.

Building current GDB-7.0.1 release is one possible solution. Just be sure to read this.

Source Link

answered Jan 23, 2010 at 5:46

Employed Russian

216.9k
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324
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