Revisions to Convert hex string to integer in Python

formatting

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edited Jan 23, 2021 at 9:19

user3064538

int(hexStringhexstring, 16) does the trick, and works with and without the 0x prefix:

>>> int("a", 16)
10
>>> int("0xa", 16)
10

int(hexString, 16) does the trick, and works with and without the 0x prefix:

>>> int("a", 16)
10
>>> int("0xa",16)
10

int(hexstring, 16) does the trick, and works with and without the 0x prefix:

>>> int("a", 16)
10
>>> int("0xa", 16)
10

missing closing bracket

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edited Jan 8, 2013 at 4:37

int(hexString, 16) does the trick, and works with and without the 0x prefix:

>>> int("a", 16)
10
>>> int("0xa",16)
10

int(hexString, 16) does the trick, and works with and without the 0x prefix:

>>> int("a", 16)
10
>>> int("0xa",16
10

int(hexString, 16) does the trick, and works with and without the 0x prefix:

>>> int("a", 16)
10
>>> int("0xa",16)
10

Added sample REPL

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edited Apr 2, 2012 at 9:05

int(hexString, 16) does the trick, and works with and without the 0x prefix.:

>>> int("a", 16)
10
>>> int("0xa",16
10

int(hexString, 16) does the trick, and works with and without the 0x prefix.

int(hexString, 16) does the trick, and works with and without the 0x prefix:

>>> int("a", 16)
10
>>> int("0xa",16
10

Source Link

answered Oct 16, 2008 at 17:32

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