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I think, this is almost the same idea as @Travesty3. I got the same NULL.

Vishwa
– Vishwa

2013-11-22 20:15:49 +00:00
Commented Nov 22, 2013 at 20:15
If you manuually remove that part from the string and run it though JSONLint or similar, to you get valid JSON?

Mike Brant
– Mike Brant

2013-11-22 20:16:56 +00:00
Commented Nov 22, 2013 at 20:16
Yes, I tries that. It said, there should be quotes over fieldNames. Thats what I mentioned in the question earlier.

Vishwa
– Vishwa

2013-11-22 20:21:23 +00:00
Commented Nov 22, 2013 at 20:21
@VishwaDatta Sorry I missed that part. You either need to change the JSON that is created (if you have control over this) or you might need to look into another library to use for JSON decoding that is more leninent.

Mike Brant
– Mike Brant

2013-11-22 20:28:34 +00:00
Commented Nov 22, 2013 at 20:28

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create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
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indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
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