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This answer sends people in completely the wrong direction. They should never use regEx to locate regular expressions, because it cannot work correctly in all cases. See my answer added.

vitaly-t
– vitaly-t

2016-01-02 18:07:34 +00:00
Commented Jan 2, 2016 at 18:07
3

.{,1} is unmatched. Change to ^((?:(?:[^?+*{}()[\]\\|]+|\\.|\[(?:\^?\\.|\^[^\\]|[^\\^])(?:[^\]\\]+|\\.)*\]|$(?:\?[:=!]|\?<[=!]|\?>)?(?1)??$|$\?(?:R|[+-]?\d+)$)(?:(?:[?+*]|\{\d*(?:,\d*)?\})[?+]?)?|\|)*)$ matches. CHange \d+ to \d*

yunzen
– yunzen

2017-03-16 11:34:12 +00:00
Commented Mar 16, 2017 at 11:34
7

regex by def should not have recursion, at least say something like that in ur answer, ur regex engine is probably "too powerful" and not really a regex engine.

Charlie Parker
– Charlie Parker

2017-06-11 00:34:49 +00:00
Commented Jun 11, 2017 at 0:34
2

@vitaly-t: Where is your answer?

Peter V. Mørch
– Peter V. Mørch

2021-01-05 21:41:35 +00:00
Commented Jan 5, 2021 at 21:41
3

@PeterV.Mørch I deleted it, because oddly enough, it received many downvotes. Here, I copied my answer to a Gist.

vitaly-t
– vitaly-t

2021-01-06 01:29:41 +00:00
Commented Jan 6, 2021 at 1:29

| Show 5 more comments

Correct minor typos or mistakes
Clarify meaning without changing it
Add related resources or links
Always respect the author’s intent
Don’t use edits to reply to the author

create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
_italic_ or **bold**
indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
to make links (use https whenever possible)

<https://example.com>

[example](https://example.com)

<a href="https://example.com">example</a>

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