You can't directly. The closest you can get is to put the value in an object, and pass the reference (by value, so the reference gets copied) into the method.
void func()
{
int x = 3;
int[] holder = [x];
add_one(holder);
// now holder[0] is 4. x is still 3.
}
// container here is a copy of the reference holder in the calling scope.
// both container and holder point to the same underlying array object
void add_one(int[] container)
{
container[0]++;
}
Here I use an array, but the wrapper an by onycan be any object.