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  • The / operator in Python is defined as standard matrix division for square matrices, i.e., A*inv(B). In her example, she's trying to achieve right division for any size matrices. So your code would not work. Commented Jun 16, 2009 at 14:38
  • +1 for the change, and translating my math into Python code. :) I don't know Python, but in any case, I wanted her to work that out, so I didn't bother to post code along with my math. Commented Jun 16, 2009 at 15:20
  • This at least gives me a result matrix c with the right dimensions, but the values in that matrix do not match the values in Matlab- any ideas? Commented Jun 16, 2009 at 15:26
  • did you make sure that the A and B you use in numpy are the same A and B you used in matlab? Commented Jun 16, 2009 at 16:02
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    You should NOT do this. The so called normal equations should not be implemented directly, but should use the least square approximation, which is lstsq function in numpy.linalg. Commented Jun 16, 2009 at 16:04