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In reference to your last sentence, by default foo will not give warnings, but some static type analyzers have strict options to force a type annotation to be present everywhere, causing an unannotated foo to be an error.

Mario Ishac
– Mario Ishac

2020-09-10 05:00:23 +00:00
Commented Sep 10, 2020 at 5:00
@MarioIshac: I suspected that, changed my answer accordingly, thanks!

Doc Brown
– Doc Brown

2020-09-10 06:05:34 +00:00
Commented Sep 10, 2020 at 6:05

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