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Nov 15, 2023 at 23:30 comment added gnasher729 You could have a function timesfactorial(x, n) which returns x * n! That function could call timesfactorial (x*n, n-1) which is tail recursive.
Jan 10, 2016 at 17:54 comment added Deduplicator @Ixrec: A good optimizers might sometimes inline a call, tail-call or not, and/or replace recursion with a loop.
Jan 10, 2016 at 17:50 comment added Ixrec I'm trying to think of any way an aggressively optimizing compiler could do better, but it does seem like this is probably about it. The best I can come up with is that in the return n+f(); case, maybe the compiler could keep an int hanging around that it adds n to on every f() call because it knows that n+...+n+f() reduces to xn+f() and that last addition can wait until the final f() call. But that seems unlikely to be worth the effort.
Jan 10, 2016 at 17:29 history answered Bart van Ingen Schenau CC BY-SA 3.0