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So that's how actual regex engine works. It creates an NFA but store states everytime it tries to "branch" out. Is this true?user4951– user49512015-11-09 14:41:51 +00:00Commented Nov 9, 2015 at 14:41
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@JimThio how exactly it does its backtracking is an implementation detail. One way would be to push the state on a stack another would be to use recursion and use the application stack as the stack.ratchet freak– ratchet freak2015-11-09 14:53:37 +00:00Commented Nov 9, 2015 at 14:53
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so real regex engine uses stack. Interesting. Hmmm... Any references he he he he.user4951– user49512015-11-09 15:52:56 +00:00Commented Nov 9, 2015 at 15:52
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@JimThio the Java compiled regular expression state machine and stack can be seen in the Pattern class.user40980– user409802015-11-09 21:27:41 +00:00Commented Nov 9, 2015 at 21:27
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1A practical article I like on this subject describes how the NFA of a regexp can be translated to instructions. The instructions are 'char c', 'match' 'jmp x' and 'split x,y'. The 'jmp x' instruction jumps to the label x. The 'split x,y' instruction jumps to both label x and label y. The article is here The article also describes a handful of interpreters for the instructions, in historic implementations. I myself branched off from it to write a glob matcher that implemented the characters of the glob pattern as the instructions.cardiff space man– cardiff space man2015-11-09 23:54:57 +00:00Commented Nov 9, 2015 at 23:54
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