I think you're on the right track with your parametric equation.

What you have there is the vector form of the line equation.

L = R + tV

Where R is [x0, y0, z0] and V is [a, b, c].

You just need to normalize your equations. You would do that by finding the value of R such that |R| is at a minimum, which occurs when R is perpendicular to L, or R.L = 0.

Also, since t can be scaled by any value, without changing the line, you should normalize V by dividing every coefficient by |V|

I think you're on the right track with your parametric equation.

What you have there is the vector form of the line equation.

L = R + tV

Where R is [x0, y0, z0] and V is [a, b, c].

You just need to normalize your equations. You would do that by finding the value of R such that |R| is at a minimum, which occurs when R is perpendicular to V, or R.V = 0.

Also, since t can be scaled by any value, without changing the line, you should normalize V by dividing every coefficient by |V|

I think you're on the right track with your parametric equation.

What you have there is the vector form of the line equation.

L = R = tV

Where R is x0, y0, z0 and V is a, b, c.

You just need to normalize your equations. You would do that by finding the value of R such that |R| is at a minimum, which occurs when R is perpendicular to L, or R.L = 0.

Also, since t can be scaled by any value, without changing the line, you should normalize V by dividing every coefficient by |V|

I think you're on the right track with your parametric equation.

What you have there is the vector form of the line equation.

L = R + tV

Where R is [x0, y0, z0] and V is [a, b, c].

You just need to normalize your equations. You would do that by finding the value of R such that |R| is at a minimum, which occurs when R is perpendicular to L, or R.L = 0.

Also, since t can be scaled by any value, without changing the line, you should normalize V by dividing every coefficient by |V|