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  • $\begingroup$ Your question is not very clear about the actual range of numbers that should be stored. As it stands, the maximum number of bits to represent only $-32$ and $+32$ is a single bit. I guess this is not what you are asking for. If you want to store any number in that range (inclusively), you'd need 7 bits. (32 (negative values) + 1 (zero) + 32 (positive values)). For a 6-bit solution, you'd have to drop the $+32$. $\endgroup$ Commented Nov 24, 2019 at 10:09
  • $\begingroup$ sir 0 is a bit, 1 is also a bit. Minimum number of bits required to store +32(0100000) is 7 bits. Right most bit 0 to indicate sign bit. I am asking number of bits required to store -32 in signed two complement form, signed 1 complement form and signed magnitude form $\endgroup$ Commented Nov 24, 2019 at 11:59