Prompted by this question on Stackoverflow, I wrote an implementation in Python of the longest decreasing subsequence problem. In a nutshell, the problem is: given a sequence of numbers, remove the fewest possible to obtain an increasing subsequence (the answer is not unique). Perhaps it is best illustrated by example.
>>> elems
[25, 72, 31, 32, 8, 20, 38, 43, 85, 39, 33, 40, 98, 37, 14]
>>> subsequence(elems)
[25, 31, 32, 38, 39, 40, 98]
The code below works, but I am sure it could be made shorter and / or more readable. Can any more experienced Python coders offer some suggestions?
from random import randrange
from itertools import islice
def randomSeq(max):
while True: yield randrange(max)
def randomList(N,max):
return list(islice(randomSeq(max),N))
## Returns the longest subsequence (non-contiguous) of X that is strictly increasing.
def subsequence(X):
L = 1 ## length of longest subsequence (initially: just first element)
M = [0] ## M[j] = index in X of the final member of the lowest subsequence of length 'j' yet found
P = [-1]
for i in range(1,X.__len__()):
## Find largest j <= L such that: X[M[j]] < X[i].
## X[M[j]] is increasing, so use binary search over j.
j = -1
start = 0
end = L - 1
going = True
while going:
if (start == end):
if (X[M[start]] < X[i]):
j = start
going = False
else:
partition = 1 + ((end - start - 1) / 2)
if (X[M[start + partition]] < X[i]):
start += partition
j = start
else:
end = start + partition - 1
if (j >= 0):
P.append(M[j])
else:
P.append(-1)
j += 1
if (j == L):
M.append(i)
L += 1
if (X[i] < X[M[j]]):
M[j] = i
## trace subsequence back to output
result = []
trace_idx = M[L-1]
while (trace_idx >= 0):
result.append(X[trace_idx])
trace_idx = P[trace_idx]
return list(result.__reversed__())
l1 = randomList(15,100)