Timeline for Account view with MVC and paging
Current License: CC BY-SA 3.0
11 events
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| Dec 12, 2014 at 18:47 | history | edited | Vsevolod Goloviznin | CC BY-SA 3.0 |
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| Dec 12, 2014 at 18:47 | comment | added | Vsevolod Goloviznin | @SteveMichael I agree with you, but without the knowledge of the OPs architecture it's the best (of the worst) solution. I'll edit the answer to reflect this point | |
| Dec 12, 2014 at 18:41 | comment | added | Steve Michael | Using ViewBag is really an anti pattern. You should always use strongly typed view models. | |
| Dec 10, 2014 at 21:06 | history | edited | Vsevolod Goloviznin | CC BY-SA 3.0 |
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| Dec 10, 2014 at 12:24 | vote | accept | Altuğ Gülsepet | ||
| Dec 10, 2014 at 12:18 | comment | added | Vsevolod Goloviznin |
You can just do @Url.Action("Index", "Account", new { accountListFilter = ViewBag.Filter}. If you want to change the value, jsut do ViewBag.Filter.yourvalue = "something"
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| Dec 10, 2014 at 12:02 | comment | added | Altuğ Gülsepet | I mean my code must be according to your answer: @Url.Action("Index","Account",new{ViewBag.Filter}). But at this action i change the one value of ViewBag.Filter . Namely, @Url.Action("Index","Account",new{ViewBag.Filter.sortOder="Username asc"}). But at this code i am sending a one parameter. I wanna send amended ViewBag.Filter Model. | |
| Dec 10, 2014 at 11:55 | comment | added | Vsevolod Goloviznin | If you change the values, then you have some sort of a form or what? | |
| Dec 10, 2014 at 11:54 | comment | added | Altuğ Gülsepet | Thanks. But What about @Url.Action("Index", "Account", new { pagesize = currentPageSize, sortOrder = "UserName asc", usernameFilter = @currentUsernameFilter...}. This is the main problem. I change the value and send model. How is be my Url.Action? | |
| Dec 10, 2014 at 11:30 | review | First posts | |||
| Dec 10, 2014 at 11:32 | |||||
| Dec 10, 2014 at 11:26 | history | answered | Vsevolod Goloviznin | CC BY-SA 3.0 |