N >=≥ 6 would have to be the sum of two odd primes. An odd number xx is prime with probability about 2/ln xx. XX and nn - xx are two primes with probability about 1 / ln^2 nln² n, so you need to examine about ln^2 nln² n pairs of numbers to find a pair of primes.
So that shows that creating a sieve of size nn is very inefficient. It takes nn steps when you usually need just ln^2 nln² n. So create one sieve for the numbers c x ln^2 ncxln² n and one for the numbers nn - c x ln^2 ncx ln² n to nn. Experiment to find a “c”“c” that usually finds a solution, and if it doesn’t work then repeat with 2c2c instead of cc.
Now if you wanted to check all even 6 <= N <= 10^9≤ N ≤ 10⁹ then you would create one large sieve.
 
                