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\(L,n,A=expand.grid(rep(list(L),n)))A[rowSumsA[!rowSums(A[,-n]==A[,-1])==0],]
Assuming L is a vector of characters.
L
-1 byte thanks to @pajonk!
Try it online here!
\(L,n,A=expand.grid(rep(list(L),n)))A[rowSums(A[,-n]==A[,-1])==0]
\(L,n,A=expand.grid(rep(list(L),n)))A[!rowSums(A[,-n]==A[,-1]),]
Assuming L is a charactervector of stringscharacters.
Assuming L is a character of strings.
